""" Geometry functions """ from typing import Tuple import math def min_radius_contraction_span_pos( d_open: float, d_closed: float, theta: float, ) -> Tuple[float, float]: """ Calculates the position of the two ends of an actuator, whose fully opened length is `d_open`, closed length is `d_closed`, and whose motion spans a range `theta` (in radians). Returns (r, phi): If one end of the actuator is held at `(r, 0)`, then the other end will trace an arc `r` away from the origin with span `theta` Let `P` (resp. `P'`) be the position of the front of the actuator when its fully open (resp. closed), `Q` be the position of the back of the actuator, we note that `OP = OP' = OQ`. """ assert d_open > d_closed assert 0 < theta < math.pi pq2 = d_open * d_open p_q2 = d_closed * d_closed # angle of PQP' psi = 0.5 * theta # |P-P'|, via the triangle PQP' pp_2 = pq2 + p_q2 - 2 * d_open * d_closed * math.cos(psi) r2 = pp_2 / (2 - 2 * math.cos(theta)) # Law of cosines on POQ: phi = math.acos(1 - pq2 / 2 / r2) return math.sqrt(r2), phi def min_tangent_contraction_span_pos( d_open: float, d_closed: float, theta: float, ) -> Tuple[float, float, float]: """ Returns `(r, phi, r')` where `r` is the distance of the arm to origin, `r'` is the distance of the base to origin, and `phi` the angle in the open state. """ assert d_open > d_closed assert 0 < theta < math.pi # Angle of OPQ = OPP' pp_ = d_open - d_closed pq = d_open p_q = d_closed a = (math.pi - theta) / 2 # Law of sines on POP' r = math.sin(a) / math.sin(theta) * pp_ # Law of cosine on OPQ oq = math.sqrt(r * r + pq * pq - 2 * r * pq * math.cos(a)) # Law of sines on OP'Q. Not using OPQ for numerical reasons since the angle # `phi` could be very close to `pi/2` phi_ = math.asin(math.sin(a) / oq * p_q) phi = phi_ + theta assert theta <= phi < math.pi return r, phi, oq